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Acenegsurfav

He could've just read it twice tho, what an Idiot šŸ¤£


RoundEarth-is-real

That would still only solve 75% of your problems


Acenegsurfav

Then read it five more times


Louie2543

You only solve 99.22% (99.21875% rounded) of your problems


Acenegsurfav

Good enough, I'm pretty chill with life as it is. If I removed even half my problems I'd be living better than most millionaires... 99.2% is kinda excessive


Consistent_Spring700

No matter how good your life is, you'll fixate on your biggest few problems


Acenegsurfav

Idk šŸ˜ probably depends on the person... I don't find myself fixating on any of my problems


babychang

But than a bitch ain't one


jaymwtsn

I got 99 problems, but .22 ain't one.


izi_pootis

It can solve lim100% of your problems if you read it infinite times


FBI-OPEN-UP-DIES

1\n, diverges to infinity. It solves infinite problems.


gloomygl

This is not 1/n this is 1/2^n


Kaincee

What language are you guys speaking?!


XeroUnhinged

Simple math or Algebra with the limit one


Capstoner_1

Uh, no that would be statistics


XeroUnhinged

Really? I take stats next year, but we talked about limits in Algebra 2 a couple years back. If it is a stats concept then mb


Possible_Pain_9705

Which definitely convergesā€¦ right? Itā€™s been a while since Calc 2.


gloomygl

Yeah it converges very fast


YMHGreenBan

Please. Lindsay Lohan taught us the limit does not exist


mutantexx

I need 20 of those books.


TheEndlessRiver13

Still wouldn't solve 100% of your problems Also, since it operates on proportions, having more problems doesn't require buying more books.


Logica_1

I got 99 problems and a book ain't one.


goddamnaged

Hit me!


-Inner-Potential-

Easy, you repeat until you have only one problem left, that problem being lack of storage space for books. Then you go and buy a bookshelf, last problem solved gg


oh_i_cant_change_it

IM STUPID I DONT GET IT


maria_pi_

After you solve 50 % of your problems you still have 50% of problems left. Now with the second book you solve half of those 50% which is 25%. 50+25=75


Iriez_khai

At what point it will be just like a Zeno's Paradox


temporary_name1

All you need is the ability to buy infinite books and your problems will be solved


Competitive_Force529

Until that 0.1% recurring factor becomes sentient.


Confused_teen3887

the remaining percentage of the problem will be your empty wallet


LilooJedi

Not if one of the solutions was to put more money in your wallet.


UnnaturalGeek

Then adds a whole new set of problems putting you back where you started


IlllIIlIlIIllllIl

Then you're left with the problem of storing an infinite number of books


MarvelNerdess

Sorry if this is dumb, but is Zenos paradox the one about halfway to the wall, then half again, then half...?


Iriez_khai

Yeah something like that


rumbellina

Thank you! Iā€™m shamefully incompetent when it comes to math!


oh_i_cant_change_it

oh THANK YOU ! I'm ashamed now.


All2017

If thatā€™s the case then the first book only solved 25% too


CharlesTheGreat8

same


Iborrador

buy one, read it 30 times


zaeroraplayz

It will still be less than 100


ThornTintMyWorld

It will always be ~~too soon~~ <100.


aussie_nub

There becomes a point where your time spent reading the book becomes a problem of its own.


AdunfromAD

Forever approaching


CookieArtzz

Asymptotic problems


DoormatTheVine

Not if you read them both at the same time!


tenchineuro

Actually, it's still 50%, the second book won't solve anything the first book already solved or that the first book didn't solve. Now maybe if there was a volume 2?


Lyde02

Was looking for this comment :)


HydroTyler2842

What if he reads both books at the same time? šŸ¤”


BanjoSlams

Yeah, but even if you solved half of your problems, what remains are now still all of your problems. You perpetually have %100 problems left.


Murbyk

Huh, am I stupid, it only ever halfes?


Xx_Dicklord_69_xX

The difference between multiplicative and additive. Multiplicative means, you either apply one factor after the other or you first multiply all factors with each other and then multiply your value with that result. Additive means, you simply add all factors together and then multiply the value by that. Example Multiplicative: say you have 5 instances of multiplied by 2 and your Starting value is 1. That would result in 32, as you would double the number a total of 5 times, so 2, 4, 8, 16, 32. If your system instead uses additive multiplication your end result would be 10, as you would first add all multipliers together, 2+2+2+2+2=10 and multiplying that by 1 equals 10. In this post, the comment assumes multiplicative division, as the division factor is cut in half every step. If it was instead additive, you would add 50 % to 50 % which results in 100 %. I'm sure somebody can explain this better and in less words, but i just wanted to throw my 2 cents in.


Murbyk

I see. And in this specific case, do you think it's additive or multiplicative?


Xx_Dicklord_69_xX

It's definitely multiplicative. 50 % can be written as 0,5, so that means 0,5 x 0,5 = 0,25. The first application of 50 % gives you 50 %. The second application divides what you get by 50 % so in the 2nd step you only get 25%. 50% + 25% = 75% If it was additive, there would be no 1st and 2nd calculation. The 50 % of the 1st and 2nd application simply get added together so you would have 50% + 50% = 100% So, as i said, the comment in the original post assumes multiplicatice division. As to whether the books should be treated as multiplicative or additive, i personally would say additive, assuming the 2 books would contain different knowledge. In this case, one book would solve 50% of your issues while the other book would solve the other 50%.


Murbyk

So, long story short, I'm not dumb.


Xx_Dicklord_69_xX

Ye


Murbyk

Nice.


SpellDostoyevsky

As problems approach 0... BOOKS BECOME INFINITE.


ApeLover1986

/r/technicallythetruth


Fireyjon

I was going to suggest r/theydidthemath


arbogasts

Reminds me of the joke in my blue heaven. Steve Martin is asked why he has 26 copies of a silent book in his trunk. He replies in case I want to read it more than once


No_End_7351

I love that movie. "I'm witchu. I'm undercover."


Unlikely_Ad_4767

Seem legit to me!


Nothing2NV

Hahahahah nice


fleaflaa

Have to buy an infinite number of books.


YellowTintedGlasses

Read this book. Iā€™ve now got 49.5 problems


Lgrns

Th 怌Green Green Grass Of Home怍Book


ReaperOfGamess

I mean if you can read 2 books at a time 100% of problems can go away


Key_Mycologist121

I spent like 30 seconds trying to use the X on the left to close this


Glittering-Spend-786

Not if read it twice simultaneously. Then it would be 100%


E-Plurbis-DumbDumb

If you read both books simultaneously, would you solve all your problems at once?


are_my_next_victim

I say you buy them at the same time. Then they both are -50% of the original value.


revdemonhorse

But what if it was the same 50% twice?


THEESKELETONGOD

Ngl reading through the comments made me realise this post accedentaly made a modern version of that old (cant recall if it was greek or Roman) paradox of the turtle and your athlete racing home


Yoav_Friedman

r/clevercomebacks


dumpyfangirl

Keep reading and buying until your only problem is how much time and money you wasted.


RTooDeeTo

If they ready it one after the other it would be 75%, but then you'd just by one book and re-read it. thats why you gotta buy 2, read both at the same time. I'd buy 3 that way im set for a long time


StemEngineer311

He could buy 12, which would get it to 99.998% solved...


carldubs

Problem is you never reach the end of the book. just get infinitely closer with each turn of the page.


Shot_Calligrapher103

"Urge to kill rising" - Homer Simpson


Harebell101

This is amazing.šŸ¤£šŸ¤£šŸ¤£


No-Astronomer6610

Read two books simultaneously


Space_Captain_Brian

Actually it'd be 75% Ā±25% I believe. šŸ„“


Galvanized-Sorbet

Youā€™d never solve all your problems


InfectedPickles

life doesnt exist without bad things otherwize everything would be boring.