Think of 3-4-5 as the max you can bet. Just try to keep it even on the 5&9 and evenly divisible by 5 for the 6&8 (if not you’ll be stuck on the short end). Never seen a casino care if you bet any amount as long as it’s no more than 3x-4x-5x. Cheers!
You can play whatever odds as long as you don’t exceed the max odds.
So for your example, if the point is 4, your max odds behind is $15.
If you put $6 odds your payout is $12; $7 pays $14 and $8 pays $26. Remember 4 and 10 pays 2 to 1 on the odds.
If your point is 5 or 9 with a $5 pass line your max odds are $20. Pays 3 to 2
If you have $5 out there you will only get paid $7 as they don’t have fifty cent pieces. Some casino do some don’t.
$6 pays $9, $7 pays $10 with you being shorted again fifty cents, $8 pays you $12. Hence the idea of keeping your odds even numbers.
In the 6 and 8 it pays 6 to 5 max odds if playing $5 is $25.
$6 pays $7 ,$7 pays $8 and $8 pays $9
Max Odds is the max bet you can put behind, if you wanted to you could do a $50 pass and $5 in odds. Not the optimal choice but hey people play the horn all the time.
If the point is 4 on at 3x-4x-5x table, the most odds you can put behind it would be $15 (this is also true of the 10 as well). For a 5 or 9, the max would be $20. For a 6 or 8, the max would be $25.
You also should put the correct odds for the number. I use this to remember: if the point is odd, the odds must be even. So for the 5 or 9, if you had $5 odds and it hit the dealers would most likely ask you to drop $1 so that the odds will pay out correctly. To avoid this make your odds on the 5 and 9 even. So don’t put $5, put $6, $10, etc. The dealers will help you out on this too.
Pro tip for ensuring proper payout if you do max 345x odds:
Your total win will always be 7x your line bet, for example, $5 pass line or come bet:
4 or 10: $15 in odds pays $30 plus $5 line = 35 (7x5)
5 or 9: $20 in odds pay $30... "
6 or 8: $25 in odds pay $30... "
Think of 3-4-5 as the max you can bet. Just try to keep it even on the 5&9 and evenly divisible by 5 for the 6&8 (if not you’ll be stuck on the short end). Never seen a casino care if you bet any amount as long as it’s no more than 3x-4x-5x. Cheers!
Thanks a lot !
You can play whatever odds as long as you don’t exceed the max odds. So for your example, if the point is 4, your max odds behind is $15. If you put $6 odds your payout is $12; $7 pays $14 and $8 pays $26. Remember 4 and 10 pays 2 to 1 on the odds. If your point is 5 or 9 with a $5 pass line your max odds are $20. Pays 3 to 2 If you have $5 out there you will only get paid $7 as they don’t have fifty cent pieces. Some casino do some don’t. $6 pays $9, $7 pays $10 with you being shorted again fifty cents, $8 pays you $12. Hence the idea of keeping your odds even numbers. In the 6 and 8 it pays 6 to 5 max odds if playing $5 is $25. $6 pays $7 ,$7 pays $8 and $8 pays $9
I appreciate it !
Max Odds is the max bet you can put behind, if you wanted to you could do a $50 pass and $5 in odds. Not the optimal choice but hey people play the horn all the time.
Ty sir !
Just remember that many casinos require odds to be a table minimum bet. So if you play a $10 table you can not have a $5 odds bet.
If the point is 4 on at 3x-4x-5x table, the most odds you can put behind it would be $15 (this is also true of the 10 as well). For a 5 or 9, the max would be $20. For a 6 or 8, the max would be $25. You also should put the correct odds for the number. I use this to remember: if the point is odd, the odds must be even. So for the 5 or 9, if you had $5 odds and it hit the dealers would most likely ask you to drop $1 so that the odds will pay out correctly. To avoid this make your odds on the 5 and 9 even. So don’t put $5, put $6, $10, etc. The dealers will help you out on this too.
Pro tip for ensuring proper payout if you do max 345x odds: Your total win will always be 7x your line bet, for example, $5 pass line or come bet: 4 or 10: $15 in odds pays $30 plus $5 line = 35 (7x5) 5 or 9: $20 in odds pay $30... " 6 or 8: $25 in odds pay $30... "